Physics

Chapter 6 review

Accelerated motion:
 
 

Starting at rest

  

With an initial velocity
V(fin) = A * T  

V = V(ini) + A * T
D = ½ A * T * T  

D = V (ini) * T + ½ A * T * T
 

V (fin) = Square root ( 2 * A * D )

 V (fin) = Square root ( V(ini) * V (ini) + 2* A * D)
 

F = M A

F = M G

Coeff. Of fric. = Fric. Force/Normal Force

 T = 2 * pi * square root ( L / g )

 T = 1 / F

Problems:

        Problem #1.  An elevator has a scale in it. Find the weight it would read if a 55 kg man was in it while:

A. The elevator is accelerating upward at a rate of 2.5 m/s sq.

B. The elevator is decelerating upward at a rate of 2.5 m/s sq.

         Problem #2. A 900 kg car, starting from rest, reaches a velocity of 13.0 m/s over a 1.3 second period. What was the net force on the car during this time ?
 

Problem #3.  A pendulum is 1.5 meters long. Calculate the period and frequency of the pendulum if it is: On the Earth’s surface and on the moon’s surface where g= 1.6 m/s sq.)

Problem #4:  A pendulum is hung from a building. If the pendulum completes 2 cycles in 44 seconds, how tall is the building ?

Problem #5:  A 60 kg sailor jumps from a 100 kg boat. If the boat accelerates backward at –3 m/s , what is the acceleration of the sailor ? (negate any friction the boat has with the water.
 

CHECK YOUR ANSWERS !

BACK TO THE MAIN PAGE

BACK TO THE TWO DIMENSIONAL MOTION PAGE
 
 
 
 
 
 
 
 
 
 
 
 

ANSWERS:  1.   A.   677 N
                      B.  402 N
                2.   9000 N
                3.   A.   2.46 s/c
                      B.   6.08 s/c
                4.   120 meters
                5.   -2000 m/s sq.
 
BACK TO THE TOP